Base | Representation |
---|---|
bin | 110100101011111001… |
… | …1001000000111111111 |
3 | 101211001001221202102212 |
4 | 1221113303020013333 |
5 | 3323203343420421 |
6 | 123550553211035 |
7 | 11113524402155 |
oct | 1512763100777 |
9 | 354031852385 |
10 | 113142170111 |
11 | 43a8a895013 |
12 | 19b17100a7b |
13 | a89149b469 |
14 | 56946373d5 |
15 | 2e22dc0e5b |
hex | 1a57cc81ff |
113142170111 has 2 divisors, whose sum is σ = 113142170112. Its totient is φ = 113142170110.
The previous prime is 113142170023. The next prime is 113142170117. The reversal of 113142170111 is 111071241311.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-113142170111 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (113142170117) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56571085055 + 56571085056.
It is an arithmetic number, because the mean of its divisors is an integer number (56571085056).
Almost surely, 2113142170111 is an apocalyptic number.
113142170111 is a deficient number, since it is larger than the sum of its proper divisors (1).
113142170111 is an equidigital number, since it uses as much as digits as its factorization.
113142170111 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 168, while the sum is 23.
The spelling of 113142170111 in words is "one hundred thirteen billion, one hundred forty-two million, one hundred seventy thousand, one hundred eleven".
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