11314307 has 2 divisors, whose sum is σ = 11314308. Its totient is φ = 11314306.

The previous prime is 11314283. The next prime is 11314313. The reversal of 11314307 is 70341311.

It is a happy number.

It is a strong prime.

It is an emirp because it is prime and its reverse (70341311) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11314307 - 2¹⁰ = 11313283 is a prime.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (11314007) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5657153 + 5657154.

It is an arithmetic number, because the mean of its divisors is an integer number (5657154).

Almost surely, 2^11314307 is an apocalyptic number.

11314307 is a deficient number, since it is larger than the sum of its proper divisors (1).

11314307 is an equidigital number, since it uses as much as digits as its factorization.

11314307 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 252, while the sum is 20.

The square root of 11314307 is about 3363.6746275465. The cubic root of 11314307 is about 224.4963681802.

Adding to 11314307 its reverse (70341311), we get a palindrome (81655618).

The spelling of 11314307 in words is "eleven million, three hundred fourteen thousand, three hundred seven".