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113143100230 = 2511314310023
BaseRepresentation
bin110100101011111011…
…0101011001101000110
3101211001010201000022201
41221113312223031012
53323204113201410
6123551025145114
711113535324656
oct1512766531506
9354033630281
10113143100230
1143a9036a906
1219b1748b19a
13a891735924
1456947da366
152e2300683a
hex1a57dab346

113143100230 has 8 divisors (see below), whose sum is σ = 203657580432. Its totient is φ = 45257240088.

The previous prime is 113143100219. The next prime is 113143100249. The reversal of 113143100230 is 32001341311.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a super-2 number, since 2×1131431002302 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 113143100198 and 113143100207.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5657155002 + ... + 5657155021.

It is an arithmetic number, because the mean of its divisors is an integer number (25457197554).

Almost surely, 2113143100230 is an apocalyptic number.

113143100230 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

113143100230 is a deficient number, since it is larger than the sum of its proper divisors (90514480202).

113143100230 is a wasteful number, since it uses less digits than its factorization.

113143100230 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 11314310030.

The product of its (nonzero) digits is 216, while the sum is 19.

Adding to 113143100230 its reverse (32001341311), we get a palindrome (145144441541).

The spelling of 113143100230 in words is "one hundred thirteen billion, one hundred forty-three million, one hundred thousand, two hundred thirty".

Divisors: 1 2 5 10 11314310023 22628620046 56571550115 113143100230