Search a number
-
+
11314312357 is a prime number
BaseRepresentation
bin10101000100110001…
…01011010010100101
31002012111212121201211
422202120223102211
5141132430443412
65110412551421
7550244032255
oct124230532245
932174777654
1011314312357
1148866a8377
122239182571
1310b4096aaa
1479492b965
15463478ca7
hex2a262b4a5

11314312357 has 2 divisors, whose sum is σ = 11314312358. Its totient is φ = 11314312356.

The previous prime is 11314312333. The next prime is 11314312369. The reversal of 11314312357 is 75321341311.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10617035521 + 697276836 = 103039^2 + 26406^2 .

It is a cyclic number.

It is not a de Polignac number, because 11314312357 - 215 = 11314279589 is a prime.

It is a super-2 number, since 2×113143123572 (a number of 21 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11314312307) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5657156178 + 5657156179.

It is an arithmetic number, because the mean of its divisors is an integer number (5657156179).

Almost surely, 211314312357 is an apocalyptic number.

It is an amenable number.

11314312357 is a deficient number, since it is larger than the sum of its proper divisors (1).

11314312357 is an equidigital number, since it uses as much as digits as its factorization.

11314312357 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 7560, while the sum is 31.

Adding to 11314312357 its reverse (75321341311), we get a palindrome (86635653668).

The spelling of 11314312357 in words is "eleven billion, three hundred fourteen million, three hundred twelve thousand, three hundred fifty-seven".