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11314330031513 is a prime number
BaseRepresentation
bin1010010010100101001010…
…0111110101010110011001
31111001122021010001201202102
42210221102213311112121
52440333221442002023
640021421555013145
72245301434313345
oct244512247652631
944048233051672
1011314330031513
11367242037aa63
12132896229a1b5
13640c24045a42
142b188b940625
151494a1e3d628
hexa4a529f5599

11314330031513 has 2 divisors, whose sum is σ = 11314330031514. Its totient is φ = 11314330031512.

The previous prime is 11314330031437. The next prime is 11314330031527. The reversal of 11314330031513 is 31513003341311.

It is a happy number.

11314330031513 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 6995136308224 + 4319193723289 = 2644832^2 + 2078267^2 .

It is a cyclic number.

It is not a de Polignac number, because 11314330031513 - 214 = 11314330015129 is a prime.

It is not a weakly prime, because it can be changed into another prime (11314330037513) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5657165015756 + 5657165015757.

It is an arithmetic number, because the mean of its divisors is an integer number (5657165015757).

Almost surely, 211314330031513 is an apocalyptic number.

It is an amenable number.

11314330031513 is a deficient number, since it is larger than the sum of its proper divisors (1).

11314330031513 is an equidigital number, since it uses as much as digits as its factorization.

11314330031513 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4860, while the sum is 29.

Adding to 11314330031513 its reverse (31513003341311), we get a palindrome (42827333372824).

The spelling of 11314330031513 in words is "eleven trillion, three hundred fourteen billion, three hundred thirty million, thirty-one thousand, five hundred thirteen".