Base | Representation |
---|---|
bin | 1010010010100101001101… |
… | …1101010001101100000011 |
3 | 1111001122022002102111110102 |
4 | 2210221103131101230003 |
5 | 2440333234033304334 |
6 | 40021423215153015 |
7 | 2245301664353102 |
oct | 244512335215403 |
9 | 44048262374412 |
10 | 11314344041219 |
11 | 367242827972a |
12 | 1328966b1576b |
13 | 640c26c0c6cb |
14 | 2b188d74a039 |
15 | 1494a32a967e |
hex | a4a53751b03 |
11314344041219 has 2 divisors, whose sum is σ = 11314344041220. Its totient is φ = 11314344041218.
The previous prime is 11314344041173. The next prime is 11314344041233. The reversal of 11314344041219 is 91214044341311.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11314344041219 is a prime.
It is a super-3 number, since 3×113143440412193 (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is not a weakly prime, because it can be changed into another prime (11314344041249) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5657172020609 + 5657172020610.
It is an arithmetic number, because the mean of its divisors is an integer number (5657172020610).
Almost surely, 211314344041219 is an apocalyptic number.
11314344041219 is a deficient number, since it is larger than the sum of its proper divisors (1).
11314344041219 is an equidigital number, since it uses as much as digits as its factorization.
11314344041219 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 41472, while the sum is 38.
The spelling of 11314344041219 in words is "eleven trillion, three hundred fourteen billion, three hundred forty-four million, forty-one thousand, two hundred nineteen".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.074 sec. • engine limits •