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11314344041219 is a prime number
BaseRepresentation
bin1010010010100101001101…
…1101010001101100000011
31111001122022002102111110102
42210221103131101230003
52440333234033304334
640021423215153015
72245301664353102
oct244512335215403
944048262374412
1011314344041219
11367242827972a
121328966b1576b
13640c26c0c6cb
142b188d74a039
151494a32a967e
hexa4a53751b03

11314344041219 has 2 divisors, whose sum is σ = 11314344041220. Its totient is φ = 11314344041218.

The previous prime is 11314344041173. The next prime is 11314344041233. The reversal of 11314344041219 is 91214044341311.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11314344041219 is a prime.

It is a super-3 number, since 3×113143440412193 (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not a weakly prime, because it can be changed into another prime (11314344041249) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5657172020609 + 5657172020610.

It is an arithmetic number, because the mean of its divisors is an integer number (5657172020610).

Almost surely, 211314344041219 is an apocalyptic number.

11314344041219 is a deficient number, since it is larger than the sum of its proper divisors (1).

11314344041219 is an equidigital number, since it uses as much as digits as its factorization.

11314344041219 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 41472, while the sum is 38.

The spelling of 11314344041219 in words is "eleven trillion, three hundred fourteen billion, three hundred forty-four million, forty-one thousand, two hundred nineteen".