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11314441301 is a prime number
BaseRepresentation
bin10101000100110010…
…01010110001010101
31002012112010011121112
422202121022301111
5141132444110201
65110415424405
7550245110222
oct124231126125
932175104545
1011314441301
114886786239
122239225105
1310b41106a7
14794962949
154634a20bb
hex2a264ac55

11314441301 has 2 divisors, whose sum is σ = 11314441302. Its totient is φ = 11314441300.

The previous prime is 11314441297. The next prime is 11314441319. The reversal of 11314441301 is 10314441311.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 6801960676 + 4512480625 = 82474^2 + 67175^2 .

It is a cyclic number.

It is not a de Polignac number, because 11314441301 - 22 = 11314441297 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11314441351) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5657220650 + 5657220651.

It is an arithmetic number, because the mean of its divisors is an integer number (5657220651).

Almost surely, 211314441301 is an apocalyptic number.

It is an amenable number.

11314441301 is a deficient number, since it is larger than the sum of its proper divisors (1).

11314441301 is an equidigital number, since it uses as much as digits as its factorization.

11314441301 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 576, while the sum is 23.

Adding to 11314441301 its reverse (10314441311), we get a palindrome (21628882612).

The spelling of 11314441301 in words is "eleven billion, three hundred fourteen million, four hundred forty-one thousand, three hundred one".