Search a number
-
+
1131444407 is a prime number
BaseRepresentation
bin100001101110000…
…0111100010110111
32220212000022221102
41003130013202313
54304122210112
6304134440315
740016055512
oct10334074267
92825008842
101131444407
11530741a25
12276b0309b
13150540242
14aa3a5d79
15694e7bc2
hex437078b7

1131444407 has 2 divisors, whose sum is σ = 1131444408. Its totient is φ = 1131444406.

The previous prime is 1131444383. The next prime is 1131444421. The reversal of 1131444407 is 7044441311.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1131444407 - 218 = 1131182263 is a prime.

It is a super-2 number, since 2×11314444072 = 2560332892263163298, which contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 1131444407.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1131444437) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 565722203 + 565722204.

It is an arithmetic number, because the mean of its divisors is an integer number (565722204).

Almost surely, 21131444407 is an apocalyptic number.

1131444407 is a deficient number, since it is larger than the sum of its proper divisors (1).

1131444407 is an equidigital number, since it uses as much as digits as its factorization.

1131444407 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5376, while the sum is 29.

The square root of 1131444407 is about 33636.9500252327. The cubic root of 1131444407 is about 1042.0240436512.

Adding to 1131444407 its reverse (7044441311), we get a palindrome (8175885718).

The spelling of 1131444407 in words is "one billion, one hundred thirty-one million, four hundred forty-four thousand, four hundred seven".