Base | Representation |
---|---|
bin | 10000011101101111011… |
… | …001000010001111110011 |
3 | 11000011110100211002120012 |
4 | 100131233121002033303 |
5 | 122014144434421002 |
6 | 2223440114005135 |
7 | 144513160536413 |
oct | 20355731021763 |
9 | 4004410732505 |
10 | 1131445232627 |
11 | 3a6930378756 |
12 | 1633468767ab |
13 | 829056c82b8 |
14 | 3ca9583a643 |
15 | 1e671406d52 |
hex | 1076f6423f3 |
1131445232627 has 2 divisors, whose sum is σ = 1131445232628. Its totient is φ = 1131445232626.
The previous prime is 1131445232537. The next prime is 1131445232629. The reversal of 1131445232627 is 7262325441311.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1131445232627 - 212 = 1131445228531 is a prime.
It is a super-2 number, since 2×11314452326272 (a number of 25 digits) contains 22 as substring.
Together with 1131445232629, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (1131445232629) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 565722616313 + 565722616314.
It is an arithmetic number, because the mean of its divisors is an integer number (565722616314).
Almost surely, 21131445232627 is an apocalyptic number.
1131445232627 is a deficient number, since it is larger than the sum of its proper divisors (1).
1131445232627 is an equidigital number, since it uses as much as digits as its factorization.
1131445232627 is an evil number, because the sum of its binary digits is even.
The product of its digits is 241920, while the sum is 41.
The spelling of 1131445232627 in words is "one trillion, one hundred thirty-one billion, four hundred forty-five million, two hundred thirty-two thousand, six hundred twenty-seven".
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