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1131445321541 is a prime number
BaseRepresentation
bin10000011101101111011…
…001010111111101000101
311000011110100222121112022
4100131233121113331011
5122014200000242131
62223440115532525
7144513161356553
oct20355731277505
94004410877468
101131445321541
113a6930429537
121633468ba145
1382905729902
143ca95860bd3
151e67142337b
hex1076f657f45

1131445321541 has 2 divisors, whose sum is σ = 1131445321542. Its totient is φ = 1131445321540.

The previous prime is 1131445321519. The next prime is 1131445321547. The reversal of 1131445321541 is 1451235441311.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1024405112641 + 107040208900 = 1012129^2 + 327170^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1131445321541 is a prime.

It is a super-2 number, since 2×11314453215412 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1131445321547) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 565722660770 + 565722660771.

It is an arithmetic number, because the mean of its divisors is an integer number (565722660771).

Almost surely, 21131445321541 is an apocalyptic number.

It is an amenable number.

1131445321541 is a deficient number, since it is larger than the sum of its proper divisors (1).

1131445321541 is an equidigital number, since it uses as much as digits as its factorization.

1131445321541 is an evil number, because the sum of its binary digits is even.

The product of its digits is 28800, while the sum is 35.

The spelling of 1131445321541 in words is "one trillion, one hundred thirty-one billion, four hundred forty-five million, three hundred twenty-one thousand, five hundred forty-one".