Base | Representation |
---|---|
bin | 10000011101110011100… |
… | …000001110100010111111 |
3 | 11000011122011122100212212 |
4 | 100131303200032202333 |
5 | 122014320120230004 |
6 | 2223451020451035 |
7 | 144514656144011 |
oct | 20356340164277 |
9 | 4004564570785 |
10 | 1131514226879 |
11 | 3a69663120a3 |
12 | 1633659a9a7b |
13 | 82916aa40ba |
14 | 3caa0a7a1b1 |
15 | 1e6774d496e |
hex | 1077380e8bf |
1131514226879 has 2 divisors, whose sum is σ = 1131514226880. Its totient is φ = 1131514226878.
The previous prime is 1131514226837. The next prime is 1131514226891. The reversal of 1131514226879 is 9786224151311.
It is a strong prime.
It is an emirp because it is prime and its reverse (9786224151311) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1131514226879 - 240 = 32002599103 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1131514226279) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 565757113439 + 565757113440.
It is an arithmetic number, because the mean of its divisors is an integer number (565757113440).
Almost surely, 21131514226879 is an apocalyptic number.
1131514226879 is a deficient number, since it is larger than the sum of its proper divisors (1).
1131514226879 is an equidigital number, since it uses as much as digits as its factorization.
1131514226879 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 725760, while the sum is 50.
The spelling of 1131514226879 in words is "one trillion, one hundred thirty-one billion, five hundred fourteen million, two hundred twenty-six thousand, eight hundred seventy-nine".
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