11315314204330 has 32 divisors (see below), whose sum is σ = 20501551408464. Its totient is φ = 4496448516096.

The previous prime is 11315314204301. The next prime is 11315314204343. The reversal of 11315314204330 is 3340241351311.

It can be written as a sum of positive squares in 8 ways, for example, as 1644937067601 + 9670377136729 = 1282551^2 + 3109723^2 .

It is a junction number, because it is equal to n+sod(n) for n = 11315314204292 and 11315314204301.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 5162487 + ... + 7020106.

Almost surely, 2^{11315314204330} is an apocalyptic number.

11315314204330 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

11315314204330 is a deficient number, since it is larger than the sum of its proper divisors (9186237204134).

11315314204330 is a wasteful number, since it uses less digits than its factorization.

11315314204330 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 12183210.

The product of its (nonzero) digits is 12960, while the sum is 31.

Adding to 11315314204330 its reverse (3340241351311), we get a palindrome (14655555555641).

The spelling of 11315314204330 in words is "eleven trillion, three hundred fifteen billion, three hundred fourteen million, two hundred four thousand, three hundred thirty".