Base | Representation |
---|---|
bin | 1010010010101001100100… |
… | …0100111001010100001111 |
3 | 1111001202022111020202020010 |
4 | 2210222121010321110033 |
5 | 2440343132041230210 |
6 | 40022135141524303 |
7 | 2245342636331205 |
oct | 244523104712417 |
9 | 44052274222203 |
10 | 11315512055055 |
11 | 367297761881a |
12 | 1329032113693 |
13 | 641081bb4b60 |
14 | 2b1960911075 |
15 | 149520ac7920 |
hex | a4a9913950f |
11315512055055 has 64 divisors (see below), whose sum is σ = 20128982372352. Its totient is φ = 5390334673920.
The previous prime is 11315512054997. The next prime is 11315512055087. The reversal of 11315512055055 is 55055021551311.
It is a happy number.
It is not a de Polignac number, because 11315512055055 - 27 = 11315512054927 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (39).
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 49654804 + ... + 49882166.
It is an arithmetic number, because the mean of its divisors is an integer number (314515349568).
Almost surely, 211315512055055 is an apocalyptic number.
11315512055055 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
11315512055055 is a deficient number, since it is larger than the sum of its proper divisors (8813470317297).
11315512055055 is a wasteful number, since it uses less digits than its factorization.
11315512055055 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 235648.
The product of its (nonzero) digits is 93750, while the sum is 39.
The spelling of 11315512055055 in words is "eleven trillion, three hundred fifteen billion, five hundred twelve million, fifty-five thousand, fifty-five".
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