Base | Representation |
---|---|
bin | 110100101100011010… |
… | …1001011111010011100 |
3 | 101211002021112112221000 |
4 | 1221120311023322130 |
5 | 3323222312042012 |
6 | 123552412310300 |
7 | 11114124525126 |
oct | 1513065137234 |
9 | 354067475830 |
10 | 113159487132 |
11 | 43a996425aa |
12 | 19b20a72390 |
13 | a894c52613 |
14 | 5696a64216 |
15 | 2e24691ddc |
hex | 1a58d4be9c |
113159487132 has 24 divisors (see below), whose sum is σ = 293376448400. Its totient is φ = 37719829008.
The previous prime is 113159487113. The next prime is 113159487137. The reversal of 113159487132 is 231784951311.
113159487132 is a `hidden beast` number, since 1 + 1 + 3 + 159 + 487 + 13 + 2 = 666.
It is a hoax number, since the sum of its digits (45) coincides with the sum of the digits of its distinct prime factors.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (113159487137) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 523886407 + ... + 523886622.
Almost surely, 2113159487132 is an apocalyptic number.
113159487132 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
113159487132 is an abundant number, since it is smaller than the sum of its proper divisors (180216961268).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
113159487132 is a wasteful number, since it uses less digits than its factorization.
113159487132 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1047773042 (or 1047773034 counting only the distinct ones).
The product of its digits is 181440, while the sum is 45.
The spelling of 113159487132 in words is "one hundred thirteen billion, one hundred fifty-nine million, four hundred eighty-seven thousand, one hundred thirty-two".
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