Base | Representation |
---|---|
bin | 10101000100111110… |
… | …10000001100000001 |
3 | 1002012122010012121112 |
4 | 22202133100030001 |
5 | 141133401130403 |
6 | 5110513533105 |
7 | 550264502426 |
oct | 124237201401 |
9 | 32178105545 |
10 | 11316036353 |
11 | 4887675666 |
12 | 2239874195 |
13 | 10b454b6cb |
14 | 794c59d4d |
15 | 4636b99d8 |
hex | 2a27d0301 |
11316036353 has 2 divisors, whose sum is σ = 11316036354. Its totient is φ = 11316036352.
The previous prime is 11316036341. The next prime is 11316036461. The reversal of 11316036353 is 35363061311.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 11094830224 + 221206129 = 105332^2 + 14873^2 .
It is an emirp because it is prime and its reverse (35363061311) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11316036353 - 24 = 11316036337 is a prime.
It is not a weakly prime, because it can be changed into another prime (11316036313) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5658018176 + 5658018177.
It is an arithmetic number, because the mean of its divisors is an integer number (5658018177).
Almost surely, 211316036353 is an apocalyptic number.
It is an amenable number.
11316036353 is a deficient number, since it is larger than the sum of its proper divisors (1).
11316036353 is an equidigital number, since it uses as much as digits as its factorization.
11316036353 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 14580, while the sum is 32.
Adding to 11316036353 its reverse (35363061311), we get a palindrome (46679097664).
The spelling of 11316036353 in words is "eleven billion, three hundred sixteen million, thirty-six thousand, three hundred fifty-three".
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