Base | Representation |
---|---|
bin | 110100101100111001… |
… | …0010100000010111111 |
3 | 101211010101200122212011 |
4 | 1221121302110002333 |
5 | 3323240412324411 |
6 | 123554143552051 |
7 | 11114410654456 |
oct | 1513162240277 |
9 | 354111618764 |
10 | 113175511231 |
11 | 43aa7697762 |
12 | 19b262bb627 |
13 | a898373133 |
14 | 5698c35b9d |
15 | 2e25ca9c21 |
hex | 1a59c940bf |
113175511231 has 2 divisors, whose sum is σ = 113175511232. Its totient is φ = 113175511230.
The previous prime is 113175511193. The next prime is 113175511249. The reversal of 113175511231 is 132115571311.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 113175511231 - 27 = 113175511103 is a prime.
It is a super-2 number, since 2×1131755112312 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 113175511193 and 113175511202.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (113175511931) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56587755615 + 56587755616.
It is an arithmetic number, because the mean of its divisors is an integer number (56587755616).
Almost surely, 2113175511231 is an apocalyptic number.
113175511231 is a deficient number, since it is larger than the sum of its proper divisors (1).
113175511231 is an equidigital number, since it uses as much as digits as its factorization.
113175511231 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 3150, while the sum is 31.
The spelling of 113175511231 in words is "one hundred thirteen billion, one hundred seventy-five million, five hundred eleven thousand, two hundred thirty-one".
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