Search a number
-
+
113181449247337 is a prime number
BaseRepresentation
bin11001101111000000011100…
…000100111101101001101001
3112211202001002210120212102011
4121233000130010331221221
5104313331102001403322
61040414501234235521
732561042552110642
oct3157003404755151
9484661083525364
10113181449247337
1133076a8a514019
121083b3a6425ba1
134b1cc70a77cb3
141dd40232c46c9
15d141989d1677
hex66f01c13da69

113181449247337 has 2 divisors, whose sum is σ = 113181449247338. Its totient is φ = 113181449247336.

The previous prime is 113181449247323. The next prime is 113181449247389. The reversal of 113181449247337 is 733742944181311.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 58424941991641 + 54756507255696 = 7643621^2 + 7399764^2 .

It is a cyclic number.

It is not a de Polignac number, because 113181449247337 - 239 = 112631693433449 is a prime.

It is not a weakly prime, because it can be changed into another prime (113181449247397) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56590724623668 + 56590724623669.

It is an arithmetic number, because the mean of its divisors is an integer number (56590724623669).

Almost surely, 2113181449247337 is an apocalyptic number.

It is an amenable number.

113181449247337 is a deficient number, since it is larger than the sum of its proper divisors (1).

113181449247337 is an equidigital number, since it uses as much as digits as its factorization.

113181449247337 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 12192768, while the sum is 58.

The spelling of 113181449247337 in words is "one hundred thirteen trillion, one hundred eighty-one billion, four hundred forty-nine million, two hundred forty-seven thousand, three hundred thirty-seven".