Base | Representation |
---|---|
bin | 100001101110111… |
… | …1010000100010101 |
3 | 2220212220011101222 |
4 | 1003131322010111 |
5 | 4304232212433 |
6 | 304152500125 |
7 | 40023051224 |
oct | 10335720425 |
9 | 2825804358 |
10 | 1131913493 |
11 | 530a323a7 |
12 | 2770aa645 |
13 | 1506758c9 |
14 | aa488cbb |
15 | 6958bb98 |
hex | 4377a115 |
1131913493 has 2 divisors, whose sum is σ = 1131913494. Its totient is φ = 1131913492.
The previous prime is 1131913483. The next prime is 1131913547. The reversal of 1131913493 is 3943191311.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 735385924 + 396527569 = 27118^2 + 19913^2 .
It is an emirp because it is prime and its reverse (3943191311) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1131913493 - 216 = 1131847957 is a prime.
It is a super-2 number, since 2×11319134932 = 2562456311270922098, which contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1131913403) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 565956746 + 565956747.
It is an arithmetic number, because the mean of its divisors is an integer number (565956747).
Almost surely, 21131913493 is an apocalyptic number.
It is an amenable number.
1131913493 is a deficient number, since it is larger than the sum of its proper divisors (1).
1131913493 is an equidigital number, since it uses as much as digits as its factorization.
1131913493 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 8748, while the sum is 35.
The square root of 1131913493 is about 33643.9220811130. The cubic root of 1131913493 is about 1042.1680281465.
The spelling of 1131913493 in words is "one billion, one hundred thirty-one million, nine hundred thirteen thousand, four hundred ninety-three".
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