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1132001032310 = 25113200103231
BaseRepresentation
bin10000011110010000100…
…001001111100001110110
311000012220002122122101122
4100132100201033201312
5122021314231013220
62224011210423542
7144533020004561
oct20362041174166
94005802578348
101132001032310
113a7096087235
12163480a31bb2
13829938b9555
143cb095994d8
151e6a50e3425
hex1079084f876

1132001032310 has 8 divisors (see below), whose sum is σ = 2037601858176. Its totient is φ = 452800412920.

The previous prime is 1132001032307. The next prime is 1132001032333. The reversal of 1132001032310 is 132301002311.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a super-2 number, since 2×11320010323102 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 56600051606 + ... + 56600051625.

It is an arithmetic number, because the mean of its divisors is an integer number (254700232272).

Almost surely, 21132001032310 is an apocalyptic number.

1132001032310 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

1132001032310 is a deficient number, since it is larger than the sum of its proper divisors (905600825866).

1132001032310 is a wasteful number, since it uses less digits than its factorization.

1132001032310 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 113200103238.

The product of its (nonzero) digits is 108, while the sum is 17.

Adding to 1132001032310 its reverse (132301002311), we get a palindrome (1264302034621).

Subtracting from 1132001032310 its reverse (132301002311), we obtain a cube (999700029999 = 99993).

The spelling of 1132001032310 in words is "one trillion, one hundred thirty-two billion, one million, thirty-two thousand, three hundred ten".

Divisors: 1 2 5 10 113200103231 226400206462 566000516155 1132001032310