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113200112300 = 225211144771119
BaseRepresentation
bin110100101101101000…
…0001010001010101100
3101211012002222112011212
41221123100022022230
53323313212043200
6124000423133552
711115130035632
oct1513320121254
9354162875155
10113200112300
114400a56a920
1219b325a42b8
13a8a04a7892
14569c1db352
152e28019035
hex1a5b40a2ac

113200112300 has 72 divisors (see below), whose sum is σ = 268164503040. Its totient is φ = 41134651200.

The previous prime is 113200112297. The next prime is 113200112303. The reversal of 113200112300 is 3211002311.

It is an interprime number because it is at equal distance from previous prime (113200112297) and next prime (113200112303).

It is a super-2 number, since 2×1132001123002 (a number of 23 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (113200112303) by changing a digit.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 1556141 + ... + 1627259.

Almost surely, 2113200112300 is an apocalyptic number.

113200112300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 113200112300, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (134082251520).

113200112300 is an abundant number, since it is smaller than the sum of its proper divisors (154964390740).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

113200112300 is a wasteful number, since it uses less digits than its factorization.

113200112300 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 72591 (or 72584 counting only the distinct ones).

The product of its (nonzero) digits is 36, while the sum is 14.

Adding to 113200112300 its reverse (3211002311), we get a palindrome (116411114611).

It can be divided in two parts, 11320011 and 2300, that added together give a palindrome (11322311).

The spelling of 113200112300 in words is "one hundred thirteen billion, two hundred million, one hundred twelve thousand, three hundred".

Divisors: 1 2 4 5 10 11 20 22 25 44 50 55 100 110 220 275 550 1100 1447 2894 5788 7235 14470 15917 28940 31834 36175 63668 71119 72350 79585 142238 144700 159170 284476 318340 355595 397925 711190 782309 795850 1422380 1564618 1591700 1777975 3129236 3555950 3911545 7111900 7823090 15646180 19557725 39115450 78230900 102909193 205818386 411636772 514545965 1029091930 1132001123 2058183860 2264002246 2572729825 4528004492 5145459650 5660005615 10290919300 11320011230 22640022460 28300028075 56600056150 113200112300