Base | Representation |
---|---|
bin | 1010010010111010010101… |
… | …0010110100101101100110 |
3 | 1111002011221002200122100111 |
4 | 2210232211102310231212 |
5 | 2440431341033000402 |
6 | 40024201451203234 |
7 | 2245562310252421 |
oct | 244564522645546 |
9 | 44064832618314 |
10 | 11320012000102 |
11 | 3674876731073 |
12 | 1329a8914651a |
13 | 64161b26c630 |
14 | 2b1c6a4049b8 |
15 | 1496d5ba49d7 |
hex | a4ba54b4b66 |
11320012000102 has 16 divisors (see below), whose sum is σ = 18333181404720. Its totient is φ = 5211190016352.
The previous prime is 11320012000091. The next prime is 11320012000163. The reversal of 11320012000102 is 20100021002311.
11320012000102 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a Harshad number since it is a multiple of its sum of digits (13).
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 559610808 + ... + 559631035.
It is an arithmetic number, because the mean of its divisors is an integer number (1145823837795).
Almost surely, 211320012000102 is an apocalyptic number.
11320012000102 is a deficient number, since it is larger than the sum of its proper divisors (7013169404618).
11320012000102 is a wasteful number, since it uses less digits than its factorization.
11320012000102 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1119242247.
The product of its (nonzero) digits is 24, while the sum is 13.
Adding to 11320012000102 its reverse (20100021002311), we get a palindrome (31420033002413).
The spelling of 11320012000102 in words is "eleven trillion, three hundred twenty billion, twelve million, one hundred two", and thus it is an aban number.
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