Base | Representation |
---|---|
bin | 10000011110010000100… |
… | …010010011111010111011 |
3 | 11000012220010011212122221 |
4 | 100132100202103322323 |
5 | 122021314313444233 |
6 | 2224011220424511 |
7 | 144533022252361 |
oct | 20362042237273 |
9 | 4005803155587 |
10 | 1132001312443 |
11 | 3a7096258751 |
12 | 163480b48137 |
13 | 82993986c01 |
14 | 3cb0962d631 |
15 | 1e6a514b42d |
hex | 10790893ebb |
1132001312443 has 2 divisors, whose sum is σ = 1132001312444. Its totient is φ = 1132001312442.
The previous prime is 1132001312419. The next prime is 1132001312473. The reversal of 1132001312443 is 3442131002311.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1132001312443 is a prime.
It is not a weakly prime, because it can be changed into another prime (1132001312413) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 566000656221 + 566000656222.
It is an arithmetic number, because the mean of its divisors is an integer number (566000656222).
Almost surely, 21132001312443 is an apocalyptic number.
1132001312443 is a deficient number, since it is larger than the sum of its proper divisors (1).
1132001312443 is an equidigital number, since it uses as much as digits as its factorization.
1132001312443 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1728, while the sum is 25.
Adding to 1132001312443 its reverse (3442131002311), we get a palindrome (4574132314754).
The spelling of 1132001312443 in words is "one trillion, one hundred thirty-two billion, one million, three hundred twelve thousand, four hundred forty-three".
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