Base | Representation |
---|---|
bin | 110100101101101000… |
… | …0111101111000011001 |
3 | 101211012010101021202002 |
4 | 1221123100331320121 |
5 | 3323313240332441 |
6 | 124000431450345 |
7 | 11115131610323 |
oct | 1513320757031 |
9 | 354163337662 |
10 | 113200324121 |
11 | 4400a6a4a85 |
12 | 19b326869b5 |
13 | a8a0550111 |
14 | 569c254613 |
15 | 2e2805bb9b |
hex | 1a5b43de19 |
113200324121 has 2 divisors, whose sum is σ = 113200324122. Its totient is φ = 113200324120.
The previous prime is 113200324117. The next prime is 113200324123. The reversal of 113200324121 is 121423002311.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 110598814096 + 2601510025 = 332564^2 + 51005^2 .
It is a cyclic number.
It is not a de Polignac number, because 113200324121 - 22 = 113200324117 is a prime.
Together with 113200324123, it forms a pair of twin primes.
It is a Chen prime.
It is a junction number, because it is equal to n+sod(n) for n = 113200324093 and 113200324102.
It is not a weakly prime, because it can be changed into another prime (113200324123) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56600162060 + 56600162061.
It is an arithmetic number, because the mean of its divisors is an integer number (56600162061).
Almost surely, 2113200324121 is an apocalyptic number.
It is an amenable number.
113200324121 is a deficient number, since it is larger than the sum of its proper divisors (1).
113200324121 is an equidigital number, since it uses as much as digits as its factorization.
113200324121 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 288, while the sum is 20.
Adding to 113200324121 its reverse (121423002311), we get a palindrome (234623326432).
The spelling of 113200324121 in words is "one hundred thirteen billion, two hundred million, three hundred twenty-four thousand, one hundred twenty-one".
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