113201100107 has 2 divisors, whose sum is σ = 113201100108. Its totient is φ = 113201100106.

The previous prime is 113201100053. The next prime is 113201100109. The reversal of 113201100107 is 701001102311.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 113201100107 - 2³⁰ = 112127358283 is a prime.

It is a super-2 number, since 2×113201100107² (a number of 23 digits) contains 22 as substring.

Together with 113201100109, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (113201100109) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56600550053 + 56600550054.

It is an arithmetic number, because the mean of its divisors is an integer number (56600550054).

Almost surely, 2^113201100107 is an apocalyptic number.

113201100107 is a deficient number, since it is larger than the sum of its proper divisors (1).

113201100107 is an equidigital number, since it uses as much as digits as its factorization.

113201100107 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 42, while the sum is 17.

Adding to 113201100107 its reverse (701001102311), we get a palindrome (814202202418).

The spelling of 113201100107 in words is "one hundred thirteen billion, two hundred one million, one hundred thousand, one hundred seven".