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113201201011200 = 2935219931479151
BaseRepresentation
bin11001101111010010110101…
…010111111101101000000000
3112211210221002100000102200220
4121233102311113331220000
5104314142024424324300
61040431525215143040
732562342201250221
oct3157226527755000
9484727070012626
10113201201011200
11330843a5904605
1210843199214a80
134b21a9abaa033
141dd4d7862d248
15d14952a65da0
hex66f4b55fda00

113201201011200 has 240 divisors, whose sum is σ = 374140978670976. Its totient is φ = 30171820032000.

The previous prime is 113201201011139. The next prime is 113201201011201. The reversal of 113201201011200 is 2110102102311.

It is a tau number, because it is divible by the number of its divisors (240).

It is a Harshad number since it is a multiple of its sum of digits (15).

It is a self number, because there is not a number n which added to its sum of digits gives 113201201011200.

It is not an unprimeable number, because it can be changed into a prime (113201201011201) by changing a digit.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 75791625 + ... + 77270775.

Almost surely, 2113201201011200 is an apocalyptic number.

113201201011200 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 113201201011200, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (187070489335488).

113201201011200 is an abundant number, since it is smaller than the sum of its proper divisors (260939777659776).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

113201201011200 is a wasteful number, since it uses less digits than its factorization.

113201201011200 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1481175 (or 1481154 counting only the distinct ones).

The product of its (nonzero) digits is 24, while the sum is 15.

Adding to 113201201011200 its reverse (2110102102311), we get a palindrome (115311303113511).

The spelling of 113201201011200 in words is "one hundred thirteen trillion, two hundred one billion, two hundred one million, eleven thousand, two hundred".