Base | Representation |
---|---|
bin | 10000011110010001001… |
… | …011001101010001001100 |
3 | 11000012220212100112122022 |
4 | 100132101023031101030 |
5 | 122021330040024400 |
6 | 2224012242305312 |
7 | 144533212343054 |
oct | 20362113152114 |
9 | 4005825315568 |
10 | 1132012033100 |
11 | 3a70a13102a3 |
12 | 163484658238 |
13 | 82995c6b7b0 |
14 | 3cb0ac20564 |
15 | 1e6a6067b85 |
hex | 107912cd44c |
1132012033100 has 72 divisors (see below), whose sum is σ = 2655965351088. Its totient is φ = 416308320000.
The previous prime is 1132012033043. The next prime is 1132012033127. The reversal of 1132012033100 is 13302102311.
It is a super-2 number, since 2×11320120331002 (a number of 25 digits) contains 22 as substring.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 1408319 + ... + 2060918.
It is an arithmetic number, because the mean of its divisors is an integer number (36888407654).
Almost surely, 21132012033100 is an apocalyptic number.
1132012033100 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
1132012033100 is an abundant number, since it is smaller than the sum of its proper divisors (1523953317988).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1132012033100 is a wasteful number, since it uses less digits than its factorization.
1132012033100 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3469515 (or 3469508 counting only the distinct ones).
The product of its (nonzero) digits is 108, while the sum is 17.
Adding to 1132012033100 its reverse (13302102311), we get a palindrome (1145314135411).
The spelling of 1132012033100 in words is "one trillion, one hundred thirty-two billion, twelve million, thirty-three thousand, one hundred".
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