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11320130333 is a prime number
BaseRepresentation
bin10101000101011101…
…10111101100011101
31002012220211012111102
422202232313230131
5141140423132313
65111141402445
7550344343301
oct124256675435
932186735442
1011320130333
114889a11516
12223b109425
1310b5352c95
14795603d01
15463c27a58
hex2a2bb7b1d

11320130333 has 2 divisors, whose sum is σ = 11320130334. Its totient is φ = 11320130332.

The previous prime is 11320130303. The next prime is 11320130347. The reversal of 11320130333 is 33303102311.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9366755524 + 1953374809 = 96782^2 + 44197^2 .

It is an emirp because it is prime and its reverse (33303102311) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11320130333 - 210 = 11320129309 is a prime.

It is a super-2 number, since 2×113201303332 (a number of 21 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11320130303) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5660065166 + 5660065167.

It is an arithmetic number, because the mean of its divisors is an integer number (5660065167).

Almost surely, 211320130333 is an apocalyptic number.

It is an amenable number.

11320130333 is a deficient number, since it is larger than the sum of its proper divisors (1).

11320130333 is an equidigital number, since it uses as much as digits as its factorization.

11320130333 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 486, while the sum is 20.

Adding to 11320130333 its reverse (33303102311), we get a palindrome (44623232644).

The spelling of 11320130333 in words is "eleven billion, three hundred twenty million, one hundred thirty thousand, three hundred thirty-three".