Base | Representation |
---|---|
bin | 10101000101011101… |
… | …10111110111000101 |
3 | 1002012220211020102121 |
4 | 22202232313313011 |
5 | 141140423143023 |
6 | 5111141405541 |
7 | 550344345262 |
oct | 124256676705 |
9 | 32186736377 |
10 | 11320131013 |
11 | 4889a11a84 |
12 | 223b1098b1 |
13 | 10b5353399 |
14 | 795604269 |
15 | 463c27d5d |
hex | 2a2bb7dc5 |
11320131013 has 2 divisors, whose sum is σ = 11320131014. Its totient is φ = 11320131012.
The previous prime is 11320130999. The next prime is 11320131041. The reversal of 11320131013 is 31013102311.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 10004400484 + 1315730529 = 100022^2 + 36273^2 .
It is an emirp because it is prime and its reverse (31013102311) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11320131013 - 221 = 11318033861 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11320131073) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5660065506 + 5660065507.
It is an arithmetic number, because the mean of its divisors is an integer number (5660065507).
Almost surely, 211320131013 is an apocalyptic number.
It is an amenable number.
11320131013 is a deficient number, since it is larger than the sum of its proper divisors (1).
11320131013 is an equidigital number, since it uses as much as digits as its factorization.
11320131013 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 54, while the sum is 16.
Adding to 11320131013 its reverse (31013102311), we get a palindrome (42333233324).
The spelling of 11320131013 in words is "eleven billion, three hundred twenty million, one hundred thirty-one thousand, thirteen".
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