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113201412044051 is a prime number
BaseRepresentation
bin11001101111010011000001…
…111100111111010100010011
3112211210221122001010000100102
4121233103001330333110103
5104314142442440402201
61040432002154243015
732562350343065312
oct3157230174772423
9484727561100312
10113201412044051
11330844a3a42721
1210843237a2646b
134b21b02828046
141dd4d98684279
15d1496634e26b
hex66f4c1f3f513

113201412044051 has 2 divisors, whose sum is σ = 113201412044052. Its totient is φ = 113201412044050.

The previous prime is 113201412044011. The next prime is 113201412044089. The reversal of 113201412044051 is 150440214102311.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-113201412044051 is a prime.

It is not a weakly prime, because it can be changed into another prime (113201412044011) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56600706022025 + 56600706022026.

It is an arithmetic number, because the mean of its divisors is an integer number (56600706022026).

Almost surely, 2113201412044051 is an apocalyptic number.

113201412044051 is a deficient number, since it is larger than the sum of its proper divisors (1).

113201412044051 is an equidigital number, since it uses as much as digits as its factorization.

113201412044051 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3840, while the sum is 29.

Adding to 113201412044051 its reverse (150440214102311), we get a palindrome (263641626146362).

The spelling of 113201412044051 in words is "one hundred thirteen trillion, two hundred one billion, four hundred twelve million, forty-four thousand, fifty-one".