113201412044011 has 2 divisors, whose sum is σ = 113201412044012. Its totient is φ = 113201412044010.

The previous prime is 113201412043969. The next prime is 113201412044051. The reversal of 113201412044011 is 110440214102311.

It is a strong prime.

It is an emirp because it is prime and its reverse (110440214102311) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 113201412044011 - 2¹⁵ = 113201412011243 is a prime.

It is not a weakly prime, because it can be changed into another prime (113201412044051) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56600706022005 + 56600706022006.

It is an arithmetic number, because the mean of its divisors is an integer number (56600706022006).

Almost surely, 2^{113201412044011} is an apocalyptic number.

113201412044011 is a deficient number, since it is larger than the sum of its proper divisors (1).

113201412044011 is an equidigital number, since it uses as much as digits as its factorization.

113201412044011 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 768, while the sum is 25.

Adding to 113201412044011 its reverse (110440214102311), we get a palindrome (223641626146322).

The spelling of 113201412044011 in words is "one hundred thirteen trillion, two hundred one billion, four hundred twelve million, forty-four thousand, eleven".