Base | Representation |
---|---|
bin | 10101000101011110… |
… | …01110011001100101 |
3 | 1002012220222221001212 |
4 | 22202233032121211 |
5 | 141140434121313 |
6 | 5111143401205 |
7 | 550345211366 |
oct | 124257163145 |
9 | 32186887055 |
10 | 11320223333 |
11 | 4889a75381 |
12 | 223b153205 |
13 | 10b5386403 |
14 | 795629b6d |
15 | 463c453a8 |
hex | 2a2bce665 |
11320223333 has 2 divisors, whose sum is σ = 11320223334. Its totient is φ = 11320223332.
The previous prime is 11320223323. The next prime is 11320223353. The reversal of 11320223333 is 33332202311.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 11276953249 + 43270084 = 106193^2 + 6578^2 .
It is a cyclic number.
It is not a de Polignac number, because 11320223333 - 212 = 11320219237 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 11320223299 and 11320223308.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11320223323) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5660111666 + 5660111667.
It is an arithmetic number, because the mean of its divisors is an integer number (5660111667).
Almost surely, 211320223333 is an apocalyptic number.
It is an amenable number.
11320223333 is a deficient number, since it is larger than the sum of its proper divisors (1).
11320223333 is an equidigital number, since it uses as much as digits as its factorization.
11320223333 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1944, while the sum is 23.
Adding to 11320223333 its reverse (33332202311), we get a palindrome (44652425644).
The spelling of 11320223333 in words is "eleven billion, three hundred twenty million, two hundred twenty-three thousand, three hundred thirty-three".
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