Base | Representation |
---|---|
bin | 110100101101101100… |
… | …0011010011011001101 |
3 | 101211012021001110021120 |
4 | 1221123120122123031 |
5 | 3323314240313140 |
6 | 124000541351153 |
7 | 11115154320135 |
oct | 1513330323315 |
9 | 354167043246 |
10 | 113202276045 |
11 | 44010808541 |
12 | 19b332684b9 |
13 | a8a0a846c1 |
14 | 569c601ac5 |
15 | 2e282e51d0 |
hex | 1a5b61a6cd |
113202276045 has 32 divisors (see below), whose sum is σ = 181866487680. Its totient is φ = 60127107840.
The previous prime is 113202276041. The next prime is 113202276067. The reversal of 113202276045 is 540672202311.
It is not a de Polignac number, because 113202276045 - 22 = 113202276041 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 113202275997 and 113202276015.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (113202276041) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 18222990 + ... + 18229200.
It is an arithmetic number, because the mean of its divisors is an integer number (5683327740).
Almost surely, 2113202276045 is an apocalyptic number.
113202276045 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
113202276045 is a deficient number, since it is larger than the sum of its proper divisors (68664211635).
113202276045 is a wasteful number, since it uses less digits than its factorization.
113202276045 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 11005.
The product of its (nonzero) digits is 20160, while the sum is 33.
Adding to 113202276045 its reverse (540672202311), we get a palindrome (653874478356).
The spelling of 113202276045 in words is "one hundred thirteen billion, two hundred two million, two hundred seventy-six thousand, forty-five".
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