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11320300217 is a prime number
BaseRepresentation
bin10101000101011111…
…00001001010111001
31002012221010211112102
422202233201022321
5141140444101332
65111145153145
7550345651502
oct124257411271
932187124472
1011320300217
11488a018116
12223b18b7b5
1310b53b23c5
14795649ba9
15463c5d062
hex2a2be12b9

11320300217 has 2 divisors, whose sum is σ = 11320300218. Its totient is φ = 11320300216.

The previous prime is 11320300177. The next prime is 11320300219. The reversal of 11320300217 is 71200302311.

11320300217 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 8003807296 + 3316492921 = 89464^2 + 57589^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11320300217 is a prime.

Together with 11320300219, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (11320300219) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5660150108 + 5660150109.

It is an arithmetic number, because the mean of its divisors is an integer number (5660150109).

Almost surely, 211320300217 is an apocalyptic number.

It is an amenable number.

11320300217 is a deficient number, since it is larger than the sum of its proper divisors (1).

11320300217 is an equidigital number, since it uses as much as digits as its factorization.

11320300217 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 252, while the sum is 20.

Adding to 11320300217 its reverse (71200302311), we get a palindrome (82520602528).

The spelling of 11320300217 in words is "eleven billion, three hundred twenty million, three hundred thousand, two hundred seventeen".