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11320314073 is a prime number
BaseRepresentation
bin10101000101011111…
…00100100011011001
31002012221011112112121
422202233210203121
5141141000022243
65111145341241
7550346040055
oct124257444331
932187145477
1011320314073
11488a027572
12223b197821
1310b53b87c3
14795650c65
15463c621ed
hex2a2be48d9

11320314073 has 2 divisors, whose sum is σ = 11320314074. Its totient is φ = 11320314072.

The previous prime is 11320314029. The next prime is 11320314101. The reversal of 11320314073 is 37041302311.

11320314073 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10934466624 + 385847449 = 104568^2 + 19643^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11320314073 is a prime.

It is a super-2 number, since 2×113203140732 (a number of 21 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (11320314013) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5660157036 + 5660157037.

It is an arithmetic number, because the mean of its divisors is an integer number (5660157037).

Almost surely, 211320314073 is an apocalyptic number.

It is an amenable number.

11320314073 is a deficient number, since it is larger than the sum of its proper divisors (1).

11320314073 is an equidigital number, since it uses as much as digits as its factorization.

11320314073 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1512, while the sum is 25.

Adding to 11320314073 its reverse (37041302311), we get a palindrome (48361616384).

The spelling of 11320314073 in words is "eleven billion, three hundred twenty million, three hundred fourteen thousand, seventy-three".