Base | Representation |
---|---|
bin | 11001101111010100101001… |
… | …000101110100101111010111 |
3 | 112211211010002122002212200022 |
4 | 121233110221011310233113 |
5 | 104314210013424211041 |
6 | 1040432450010135355 |
7 | 32562441254014451 |
oct | 3157245105645727 |
9 | 484733078085608 |
10 | 113203142413271 |
11 | 33085201768729 |
12 | 1084363b42155b |
13 | 4b2201a178661 |
14 | 1dd50c03d32d1 |
15 | d14a1820124b |
hex | 66f529174bd7 |
113203142413271 has 2 divisors, whose sum is σ = 113203142413272. Its totient is φ = 113203142413270.
The previous prime is 113203142413253. The next prime is 113203142413327. The reversal of 113203142413271 is 172314241302311.
It is a weak prime.
It is an emirp because it is prime and its reverse (172314241302311) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 113203142413271 - 214 = 113203142396887 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (113203142412271) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56601571206635 + 56601571206636.
It is an arithmetic number, because the mean of its divisors is an integer number (56601571206636).
Almost surely, 2113203142413271 is an apocalyptic number.
113203142413271 is a deficient number, since it is larger than the sum of its proper divisors (1).
113203142413271 is an equidigital number, since it uses as much as digits as its factorization.
113203142413271 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 24192, while the sum is 35.
Adding to 113203142413271 its reverse (172314241302311), we get a palindrome (285517383715582).
The spelling of 113203142413271 in words is "one hundred thirteen trillion, two hundred three billion, one hundred forty-two million, four hundred thirteen thousand, two hundred seventy-one".
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