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11320315241215 = 52264063048243
BaseRepresentation
bin1010010010111011011101…
…0111100110001011111111
31111002012201020021212221211
42210232313113212023333
52440433001200204330
640024251522505251
72245602651621331
oct244566727461377
944065636255854
1011320315241215
113674a11919662
121329b52805227
13641669033746
142b1c987bd451
15149702603d2a
hexa4bb75e62ff

11320315241215 has 4 divisors (see below), whose sum is σ = 13584378289464. Its totient is φ = 9056252192968.

The previous prime is 11320315241113. The next prime is 11320315241219. The reversal of 11320315241215 is 51214251302311.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 11320315241215 - 223 = 11320306852607 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11320315241219) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1132031524117 + ... + 1132031524126.

It is an arithmetic number, because the mean of its divisors is an integer number (3396094572366).

Almost surely, 211320315241215 is an apocalyptic number.

11320315241215 is a deficient number, since it is larger than the sum of its proper divisors (2264063048249).

11320315241215 is an equidigital number, since it uses as much as digits as its factorization.

11320315241215 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2264063048248.

The product of its (nonzero) digits is 7200, while the sum is 31.

Adding to 11320315241215 its reverse (51214251302311), we get a palindrome (62534566543526).

The spelling of 11320315241215 in words is "eleven trillion, three hundred twenty billion, three hundred fifteen million, two hundred forty-one thousand, two hundred fifteen".

Divisors: 1 5 2264063048243 11320315241215