Base | Representation |
---|---|
bin | 1010010010111011011101… |
… | …0111100110001011111111 |
3 | 1111002012201020021212221211 |
4 | 2210232313113212023333 |
5 | 2440433001200204330 |
6 | 40024251522505251 |
7 | 2245602651621331 |
oct | 244566727461377 |
9 | 44065636255854 |
10 | 11320315241215 |
11 | 3674a11919662 |
12 | 1329b52805227 |
13 | 641669033746 |
14 | 2b1c987bd451 |
15 | 149702603d2a |
hex | a4bb75e62ff |
11320315241215 has 4 divisors (see below), whose sum is σ = 13584378289464. Its totient is φ = 9056252192968.
The previous prime is 11320315241113. The next prime is 11320315241219. The reversal of 11320315241215 is 51214251302311.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 11320315241215 - 223 = 11320306852607 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11320315241219) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1132031524117 + ... + 1132031524126.
It is an arithmetic number, because the mean of its divisors is an integer number (3396094572366).
Almost surely, 211320315241215 is an apocalyptic number.
11320315241215 is a deficient number, since it is larger than the sum of its proper divisors (2264063048249).
11320315241215 is an equidigital number, since it uses as much as digits as its factorization.
11320315241215 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2264063048248.
The product of its (nonzero) digits is 7200, while the sum is 31.
Adding to 11320315241215 its reverse (51214251302311), we get a palindrome (62534566543526).
The spelling of 11320315241215 in words is "eleven trillion, three hundred twenty billion, three hundred fifteen million, two hundred forty-one thousand, two hundred fifteen".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.069 sec. • engine limits •