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11320315241113 is a prime number
BaseRepresentation
bin1010010010111011011101…
…0111100110001010011001
31111002012201020021212211001
42210232313113212022121
52440433001200203423
640024251522505001
72245602651621124
oct244566727461231
944065636255731
1011320315241113
113674a1191957a
121329b52805161
13641669033698
142b1c987bd3bb
15149702603cad
hexa4bb75e6299

11320315241113 has 2 divisors, whose sum is σ = 11320315241114. Its totient is φ = 11320315241112.

The previous prime is 11320315241107. The next prime is 11320315241219. The reversal of 11320315241113 is 31114251302311.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 11075530752064 + 244784489049 = 3327992^2 + 494757^2 .

It is a cyclic number.

It is not a de Polignac number, because 11320315241113 - 213 = 11320315232921 is a prime.

It is not a weakly prime, because it can be changed into another prime (11320315241413) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5660157620556 + 5660157620557.

It is an arithmetic number, because the mean of its divisors is an integer number (5660157620557).

Almost surely, 211320315241113 is an apocalyptic number.

It is an amenable number.

11320315241113 is a deficient number, since it is larger than the sum of its proper divisors (1).

11320315241113 is an equidigital number, since it uses as much as digits as its factorization.

11320315241113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2160, while the sum is 28.

Adding to 11320315241113 its reverse (31114251302311), we get a palindrome (42434566543424).

The spelling of 11320315241113 in words is "eleven trillion, three hundred twenty billion, three hundred fifteen million, two hundred forty-one thousand, one hundred thirteen".