Base | Representation |
---|---|
bin | 1010010010111011011101… |
… | …0111100110001100000011 |
3 | 1111002012201020021212221222 |
4 | 2210232313113212030003 |
5 | 2440433001200204334 |
6 | 40024251522505255 |
7 | 2245602651621335 |
oct | 244566727461403 |
9 | 44065636255858 |
10 | 11320315241219 |
11 | 3674a11919666 |
12 | 1329b5280522b |
13 | 64166903374a |
14 | 2b1c987bd455 |
15 | 149702603d2e |
hex | a4bb75e6303 |
11320315241219 has 2 divisors, whose sum is σ = 11320315241220. Its totient is φ = 11320315241218.
The previous prime is 11320315241113. The next prime is 11320315241281. The reversal of 11320315241219 is 91214251302311.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11320315241219 - 28 = 11320315240963 is a prime.
It is a super-2 number, since 2×113203152412192 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (11320315241419) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5660157620609 + 5660157620610.
It is an arithmetic number, because the mean of its divisors is an integer number (5660157620610).
Almost surely, 211320315241219 is an apocalyptic number.
11320315241219 is a deficient number, since it is larger than the sum of its proper divisors (1).
11320315241219 is an equidigital number, since it uses as much as digits as its factorization.
11320315241219 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 12960, while the sum is 35.
The spelling of 11320315241219 in words is "eleven trillion, three hundred twenty billion, three hundred fifteen million, two hundred forty-one thousand, two hundred nineteen".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.083 sec. • engine limits •