113204413113401 has 2 divisors, whose sum is σ = 113204413113402. Its totient is φ = 113204413113400.

The previous prime is 113204413113361. The next prime is 113204413113403. The reversal of 113204413113401 is 104311314402311.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 110206324326400 + 2998088787001 = 10497920^2 + 1731499^2 .

It is a cyclic number.

It is not a de Polignac number, because 113204413113401 - 2¹⁰ = 113204413112377 is a prime.

Together with 113204413113403, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (113204413113403) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56602206556700 + 56602206556701.

It is an arithmetic number, because the mean of its divisors is an integer number (56602206556701).

Almost surely, 2^{113204413113401} is an apocalyptic number.

It is an amenable number.

113204413113401 is a deficient number, since it is larger than the sum of its proper divisors (1).

113204413113401 is an equidigital number, since it uses as much as digits as its factorization.

113204413113401 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3456, while the sum is 29.

Adding to 113204413113401 its reverse (104311314402311), we get a palindrome (217515727515712).

The spelling of 113204413113401 in words is "one hundred thirteen trillion, two hundred four billion, four hundred thirteen million, one hundred thirteen thousand, four hundred one".