Base | Representation |
---|---|
bin | 10000011110010011101… |
… | …001100101100110101111 |
3 | 11000020000202110220020010 |
4 | 100132103221211212233 |
5 | 122021421202122120 |
6 | 2224020324224303 |
7 | 144534225264054 |
oct | 20362351454657 |
9 | 4006022426203 |
10 | 1132053551535 |
11 | 3a7112798755 |
12 | 16349653b093 |
13 | 829a174750a |
14 | 3cb1254b02b |
15 | 1e6a9a197e0 |
hex | 10793a659af |
1132053551535 has 32 divisors (see below), whose sum is σ = 1818519413760. Its totient is φ = 601351890048.
The previous prime is 1132053551533. The next prime is 1132053551539. The reversal of 1132053551535 is 5351553502311.
It is not a de Polignac number, because 1132053551535 - 21 = 1132053551533 is a prime.
It is a super-3 number, since 3×11320535515353 (a number of 37 digits) contains 333 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1132053551493 and 1132053551502.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1132053551533) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 15389112 + ... + 15462498.
It is an arithmetic number, because the mean of its divisors is an integer number (56828731680).
Almost surely, 21132053551535 is an apocalyptic number.
1132053551535 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
1132053551535 is a deficient number, since it is larger than the sum of its proper divisors (686465862225).
1132053551535 is a wasteful number, since it uses less digits than its factorization.
1132053551535 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 77487.
The product of its (nonzero) digits is 168750, while the sum is 39.
The spelling of 1132053551535 in words is "one trillion, one hundred thirty-two billion, fifty-three million, five hundred fifty-one thousand, five hundred thirty-five".
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