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11321010001121 is a prime number
BaseRepresentation
bin1010010010111110000011…
…0001111001010011100001
31111002021111122121100101012
42210233200301321103201
52440440412030013441
640024444501550305
72245626116156402
oct244574061712341
944067448540335
1011321010001121
113675239009aa7
12132a107415395
13641749c59992
142b1d22b919a9
151497435dd9eb
hexa4be0c794e1

11321010001121 has 2 divisors, whose sum is σ = 11321010001122. Its totient is φ = 11321010001120.

The previous prime is 11321010001001. The next prime is 11321010001123. The reversal of 11321010001121 is 12110001012311.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11031937102096 + 289072899025 = 3321436^2 + 537655^2 .

It is a cyclic number.

It is not a de Polignac number, because 11321010001121 - 230 = 11319936259297 is a prime.

Together with 11321010001123, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 11321010001096 and 11321010001105.

It is not a weakly prime, because it can be changed into another prime (11321010001123) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5660505000560 + 5660505000561.

It is an arithmetic number, because the mean of its divisors is an integer number (5660505000561).

Almost surely, 211321010001121 is an apocalyptic number.

It is an amenable number.

11321010001121 is a deficient number, since it is larger than the sum of its proper divisors (1).

11321010001121 is an equidigital number, since it uses as much as digits as its factorization.

11321010001121 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 12, while the sum is 14.

Adding to 11321010001121 its reverse (12110001012311), we get a palindrome (23431011013432).

The spelling of 11321010001121 in words is "eleven trillion, three hundred twenty-one billion, ten million, one thousand, one hundred twenty-one".