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113210122030 = 2511321012203
BaseRepresentation
bin110100101101111011…
…0010101111100101110
3101211012210211001221121
41221123312111330232
53323323242401110
6124001421451154
711115311105545
oct1513366257456
9354183731847
10113210122030
1144015187325
1219b35a10aba
13a8a25a09b5
14569d68515c
152e28d44cda
hex1a5bd95f2e

113210122030 has 8 divisors (see below), whose sum is σ = 203778219672. Its totient is φ = 45284048808.

The previous prime is 113210122013. The next prime is 113210122127. The reversal of 113210122030 is 30221012311.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a junction number, because it is equal to n+sod(n) for n = 113210121995 and 113210122013.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5660506092 + ... + 5660506111.

It is an arithmetic number, because the mean of its divisors is an integer number (25472277459).

Almost surely, 2113210122030 is an apocalyptic number.

113210122030 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

113210122030 is a deficient number, since it is larger than the sum of its proper divisors (90568097642).

113210122030 is a wasteful number, since it uses less digits than its factorization.

113210122030 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 11321012210.

The product of its (nonzero) digits is 72, while the sum is 16.

Adding to 113210122030 its reverse (30221012311), we get a palindrome (143431134341).

The spelling of 113210122030 in words is "one hundred thirteen billion, two hundred ten million, one hundred twenty-two thousand, thirty".

Divisors: 1 2 5 10 11321012203 22642024406 56605061015 113210122030