Base | Representation |
---|---|
bin | 1010010010111110001010… |
… | …1100011001001001101010 |
3 | 1111002021120220000210202212 |
4 | 2210233202230121021222 |
5 | 2440440443240110010 |
6 | 40024452010125122 |
7 | 2245626656132411 |
oct | 244574254311152 |
9 | 44067526023685 |
10 | 11321042113130 |
11 | 3675255152252 |
12 | 132a1161207a2 |
13 | 6417537c1079 |
14 | 2b1d27150478 |
15 | 149746333505 |
hex | a4be2b1926a |
11321042113130 has 32 divisors (see below), whose sum is σ = 21287314975104. Its totient is φ = 4326753410496.
The previous prime is 11321042113099. The next prime is 11321042113177. The reversal of 11321042113130 is 3131124012311.
It is a Harshad number since it is a multiple of its sum of digits (23).
It is a junction number, because it is equal to n+sod(n) for n = 11321042113096 and 11321042113105.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 26925857 + ... + 27343076.
It is an arithmetic number, because the mean of its divisors is an integer number (665228592972).
Almost surely, 211321042113130 is an apocalyptic number.
11321042113130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
11321042113130 is a deficient number, since it is larger than the sum of its proper divisors (9966272861974).
11321042113130 is a wasteful number, since it uses less digits than its factorization.
11321042113130 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 54269870.
The product of its (nonzero) digits is 432, while the sum is 23.
Adding to 11321042113130 its reverse (3131124012311), we get a palindrome (14452166125441).
The spelling of 11321042113130 in words is "eleven trillion, three hundred twenty-one billion, forty-two million, one hundred thirteen thousand, one hundred thirty".
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