Base | Representation |
---|---|
bin | 110100101101111101… |
… | …0000111011111110101 |
3 | 101211012212200100010102 |
4 | 1221123322013133311 |
5 | 3323324021031123 |
6 | 124001455003445 |
7 | 11115322366211 |
oct | 1513372073765 |
9 | 354185610112 |
10 | 113211111413 |
11 | 440157a26a4 |
12 | 19b36209585 |
13 | a8a285912a |
14 | 569d861941 |
15 | 2e28e8d028 |
hex | 1a5be877f5 |
113211111413 has 2 divisors, whose sum is σ = 113211111414. Its totient is φ = 113211111412.
The previous prime is 113211111407. The next prime is 113211111443. The reversal of 113211111413 is 314111112311.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 79655466289 + 33555645124 = 282233^2 + 183182^2 .
It is an emirp because it is prime and its reverse (314111112311) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 113211111413 - 216 = 113211045877 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (113211111443) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56605555706 + 56605555707.
It is an arithmetic number, because the mean of its divisors is an integer number (56605555707).
Almost surely, 2113211111413 is an apocalyptic number.
It is an amenable number.
113211111413 is a deficient number, since it is larger than the sum of its proper divisors (1).
113211111413 is an equidigital number, since it uses as much as digits as its factorization.
113211111413 is an evil number, because the sum of its binary digits is even.
The product of its digits is 72, while the sum is 20.
Adding to 113211111413 its reverse (314111112311), we get a palindrome (427322223724).
The spelling of 113211111413 in words is "one hundred thirteen billion, two hundred eleven million, one hundred eleven thousand, four hundred thirteen".
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