Base | Representation |
---|---|
bin | 11001101111011100000100… |
… | …001100011000100000110111 |
3 | 112211211212200010202101202102 |
4 | 121233130010030120200313 |
5 | 104314322330001412023 |
6 | 1040440244550132315 |
7 | 32563142632353263 |
oct | 3157340414304067 |
9 | 484755603671672 |
10 | 113211113310263 |
11 | 33088622068601 |
12 | 108450a495109b |
13 | 4b229ba66bb57 |
14 | 1dd5638c830a3 |
15 | d14d32d9d628 |
hex | 66f704318837 |
113211113310263 has 2 divisors, whose sum is σ = 113211113310264. Its totient is φ = 113211113310262.
The previous prime is 113211113310221. The next prime is 113211113310277. The reversal of 113211113310263 is 362013311112311.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 113211113310263 - 226 = 113211046201399 is a prime.
It is a super-2 number, since 2×1132111133102632 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (113211113310863) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56605556655131 + 56605556655132.
It is an arithmetic number, because the mean of its divisors is an integer number (56605556655132).
Almost surely, 2113211113310263 is an apocalyptic number.
113211113310263 is a deficient number, since it is larger than the sum of its proper divisors (1).
113211113310263 is an equidigital number, since it uses as much as digits as its factorization.
113211113310263 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1944, while the sum is 29.
Adding to 113211113310263 its reverse (362013311112311), we get a palindrome (475224424422574).
The spelling of 113211113310263 in words is "one hundred thirteen trillion, two hundred eleven billion, one hundred thirteen million, three hundred ten thousand, two hundred sixty-three".
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