Base | Representation |
---|---|
bin | 10000011110011000010… |
… | …001011010011001000111 |
3 | 11000020020011101210001001 |
4 | 100132120101122121013 |
5 | 122022101030201411 |
6 | 2224032134314131 |
7 | 144536156400415 |
oct | 20363021323107 |
9 | 4006204353031 |
10 | 1132131100231 |
11 | 3a715254518a |
12 | 1634b84b8947 |
13 | 829b4829c11 |
14 | 3cb1c9762b5 |
15 | 1e6b1736dc1 |
hex | 1079845a647 |
1132131100231 has 2 divisors, whose sum is σ = 1132131100232. Its totient is φ = 1132131100230.
The previous prime is 1132131100223. The next prime is 1132131100237. The reversal of 1132131100231 is 1320011312311.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1132131100231 - 23 = 1132131100223 is a prime.
It is a super-2 number, since 2×11321311002312 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1132131100199 and 1132131100208.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1132131100237) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 566065550115 + 566065550116.
It is an arithmetic number, because the mean of its divisors is an integer number (566065550116).
Almost surely, 21132131100231 is an apocalyptic number.
1132131100231 is a deficient number, since it is larger than the sum of its proper divisors (1).
1132131100231 is an equidigital number, since it uses as much as digits as its factorization.
1132131100231 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 108, while the sum is 19.
Adding to 1132131100231 its reverse (1320011312311), we get a palindrome (2452142412542).
The spelling of 1132131100231 in words is "one trillion, one hundred thirty-two billion, one hundred thirty-one million, one hundred thousand, two hundred thirty-one".
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