Base | Representation |
---|---|
bin | 10000011110011000010… |
… | …001111011110101111111 |
3 | 11000020020011122201222201 |
4 | 100132120101323311333 |
5 | 122022101044042442 |
6 | 2224032141252331 |
7 | 144536160511033 |
oct | 20363021736577 |
9 | 4006204581881 |
10 | 1132131237247 |
11 | 3a715262911a |
12 | 1634b85640a7 |
13 | 829b48773aa |
14 | 3cb1c9b01c3 |
15 | 1e6b17627b7 |
hex | 1079847bd7f |
1132131237247 has 2 divisors, whose sum is σ = 1132131237248. Its totient is φ = 1132131237246.
The previous prime is 1132131237203. The next prime is 1132131237253. The reversal of 1132131237247 is 7427321312311.
It is a strong prime.
It is an emirp because it is prime and its reverse (7427321312311) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1132131237247 - 27 = 1132131237119 is a prime.
It is a super-2 number, since 2×11321312372472 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1132131237047) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 566065618623 + 566065618624.
It is an arithmetic number, because the mean of its divisors is an integer number (566065618624).
Almost surely, 21132131237247 is an apocalyptic number.
1132131237247 is a deficient number, since it is larger than the sum of its proper divisors (1).
1132131237247 is an equidigital number, since it uses as much as digits as its factorization.
1132131237247 is an evil number, because the sum of its binary digits is even.
The product of its digits is 42336, while the sum is 37.
Adding to 1132131237247 its reverse (7427321312311), we get a palindrome (8559452549558).
The spelling of 1132131237247 in words is "one trillion, one hundred thirty-two billion, one hundred thirty-one million, two hundred thirty-seven thousand, two hundred forty-seven".
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