Base | Representation |
---|---|
bin | 1010010011000010100001… |
… | …1111011100010000110111 |
3 | 1111002101121111111021111111 |
4 | 2210300220133130100313 |
5 | 2441000343024420002 |
6 | 40025204121015451 |
7 | 2246000665426624 |
oct | 244605037342067 |
9 | 44071544437444 |
10 | 11322213123127 |
11 | 36757a6158405 |
12 | 132a3a2324587 |
13 | 6418ac2a51aa |
14 | 2b1dd889534b |
15 | 1497b40443d7 |
hex | a4c287dc437 |
11322213123127 has 2 divisors, whose sum is σ = 11322213123128. Its totient is φ = 11322213123126.
The previous prime is 11322213123079. The next prime is 11322213123161. The reversal of 11322213123127 is 72132131222311.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11322213123127 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11322213123167) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5661106561563 + 5661106561564.
It is an arithmetic number, because the mean of its divisors is an integer number (5661106561564).
Almost surely, 211322213123127 is an apocalyptic number.
11322213123127 is a deficient number, since it is larger than the sum of its proper divisors (1).
11322213123127 is an equidigital number, since it uses as much as digits as its factorization.
11322213123127 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 6048, while the sum is 31.
Adding to 11322213123127 its reverse (72132131222311), we get a palindrome (83454344345438).
The spelling of 11322213123127 in words is "eleven trillion, three hundred twenty-two billion, two hundred thirteen million, one hundred twenty-three thousand, one hundred twenty-seven".
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