Base | Representation |
---|---|
bin | 10101000101101101… |
… | …11011100101001011 |
3 | 1002020001210120002021 |
4 | 22202312323211023 |
5 | 141141443242103 |
6 | 5111254545311 |
7 | 550401323662 |
oct | 124266734513 |
9 | 32201716067 |
10 | 11322243403 |
11 | 4890125059 |
12 | 223b968237 |
13 | 10b5912a13 |
14 | 7959d3dd9 |
15 | 463ee3bbd |
hex | 2a2dbb94b |
11322243403 has 2 divisors, whose sum is σ = 11322243404. Its totient is φ = 11322243402.
The previous prime is 11322243397. The next prime is 11322243433. The reversal of 11322243403 is 30434222311.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11322243403 - 25 = 11322243371 is a prime.
It is not a weakly prime, because it can be changed into another prime (11322243433) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5661121701 + 5661121702.
It is an arithmetic number, because the mean of its divisors is an integer number (5661121702).
Almost surely, 211322243403 is an apocalyptic number.
11322243403 is a deficient number, since it is larger than the sum of its proper divisors (1).
11322243403 is an equidigital number, since it uses as much as digits as its factorization.
11322243403 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3456, while the sum is 25.
Adding to 11322243403 its reverse (30434222311), we get a palindrome (41756465714).
The spelling of 11322243403 in words is "eleven billion, three hundred twenty-two million, two hundred forty-three thousand, four hundred three".
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