Base | Representation |
---|---|
bin | 11001101111101000000100… |
… | …100011101110001011000111 |
3 | 112211220002221112111001122122 |
4 | 121233220010203232023013 |
5 | 104320030230102031213 |
6 | 1040450220045320155 |
7 | 32564110243254605 |
oct | 3157500443561307 |
9 | 484802845431578 |
10 | 113224004330183 |
11 | 3309303777867a |
12 | 108476a1b6605b |
13 | 4b23c932a47a6 |
14 | 1dd60dcd60875 |
15 | d15339974d08 |
hex | 66fa048ee2c7 |
113224004330183 has 2 divisors, whose sum is σ = 113224004330184. Its totient is φ = 113224004330182.
The previous prime is 113224004330053. The next prime is 113224004330251. The reversal of 113224004330183 is 381033400422311.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 113224004330183 - 246 = 42855260152519 is a prime.
It is a super-2 number, since 2×1132240043301832 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (113224004330383) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56612002165091 + 56612002165092.
It is an arithmetic number, because the mean of its divisors is an integer number (56612002165092).
Almost surely, 2113224004330183 is an apocalyptic number.
113224004330183 is a deficient number, since it is larger than the sum of its proper divisors (1).
113224004330183 is an equidigital number, since it uses as much as digits as its factorization.
113224004330183 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 41472, while the sum is 35.
Adding to 113224004330183 its reverse (381033400422311), we get a palindrome (494257404752494).
The spelling of 113224004330183 in words is "one hundred thirteen trillion, two hundred twenty-four billion, four million, three hundred thirty thousand, one hundred eighty-three".
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